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Your Porsche's Gas Mileage (In Miles Per Gallon) Is Given M(x)=5,625x21(5,6251+x)2M ^ { \prime } ( x ) = \frac { 5,625 x ^ { - 2 } - 1 } { \left( 5,625 ^ { - 1 } + x \right) ^ { 2 } }

Question 47

Multiple Choice

Your Porsche's gas mileage (in miles per gallon) is given as a function M(x) of speed x in miles per hour. It is found that
M(x) =5,625x21(5,6251+x) 2M ^ { \prime } ( x ) = \frac { 5,625 x ^ { - 2 } - 1 } { \left( 5,625 ^ { - 1 } + x \right) ^ { 2 } } .

Find M(55) M ^ { \prime } ( 55 ) , M(75) M ^ { \prime } ( 75 ) and M(95) M ^ { \prime } ( 95 ) .


A) M(55) =0.00004,M(75) =0.00028,M(95) =0M ^ { \prime } ( 55 ) = 0.00004 , M ^ { \prime } ( 75 ) = - 0.00028 , M ^ { \prime } ( 95 ) = 0
B) M(55) =0.00028,M(75) =0,M(95) =0.00004M ^ { \prime } ( 55 ) = 0.00028 , M ^ { \prime } ( 75 ) = 0 , M ^ { \prime } ( 95 ) = - 0.00004
C) M(55) =0.00004,M(75) =0,M(95) =0.00028M ^ { \prime } ( 55 ) = 0.00004 , M ^ { \prime } ( 75 ) = 0 , M ^ { \prime } ( 95 ) = - 0.00028
D) M(55) =0,M(75) =0.00028,M(95) =0.00004M ^ { \prime } ( 55 ) = 0 , M ^ { \prime } ( 75 ) = 0.00028 , M ^ { \prime } ( 95 ) = - 0.00004
E) M(55) =0,M(75) =0.00004,M(95) =0.00004M ^ { \prime } ( 55 ) = 0 , M ^ { \prime } ( 75 ) = 0.00004 , M ^ { \prime } ( 95 ) = - 0.00004

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