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Business statistics Study Set 3
Exam 16: Analysis of Variance
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Question 1
Essay
A partial ANOVA table in a randomised block design is shown below.
 Source of VariationÂ
 SSÂ
d
f
M
S
F
 TreatmentsÂ
∗
3
∗
∗
 BlocksÂ
1256
2
∗
∗
 ErrorÂ
∗
∗
67.67
 TotalÂ
2922
11
\begin{array} { | l | c | c | c | c | } \hline \text { Source of Variation } & \text { SS } & d f & M S & F \\\hline \text { Treatments } & * & 3 & * & * \\\hline \text { Blocks } & 1256 & 2 & * & * \\\hline \text { Error } & * & * & 67.67 & \\\hline \text { Total } & 2922 & 11 & & \\\hline\end{array}
 Source of VariationÂ
 TreatmentsÂ
 BlocksÂ
 ErrorÂ
 TotalÂ
​
 SSÂ
∗
1256
∗
2922
​
df
3
2
∗
11
​
MS
∗
∗
67.67
​
F
∗
∗
​
​
Can we infer at the 5% significance level that the block means differ?
Question 2
True/False
In one-way ANOVA, the total variation SS(Total) is partitioned into three sources of variation: the sum of squares for treatments (SST), the sum of squares for blocks (SSB) and the sum of squares for error (SSE).
Question 3
Multiple Choice
In a single-factor analysis of variance, MST is the mean square for treatments and MSE is the mean square for error. The null hypothesis of equal population means is likely false if:
Question 4
Essay
The strength of a weld depends to some extent on the metal alloy used in the welding process. A scientist working in the research laboratory of a major automobile manufacturer has developed three new alloys. In order to test their strengths, each alloy is used in several welds. The strengths of the welds are then measured, with the results shown below. Can the scientist conclude at the 5% significance level that differences exist among the strengths of the welds with the different alloys?
\quad
\quad
\quad
 Strength of weldsÂ
\text { Strength of welds }
 Strength of weldsÂ
 Alloy 1Â
 Alloy 2Â
 Alloy 3Â
15
17
25
23
21
27
16
19
24
29
25
31
28
23
19
\begin{array} { | c | c | c | } \hline \text { Alloy 1 } & \text { Alloy 2 } & \text { Alloy 3 } \\\hline 15 & 17 & 25 \\\hline 23 & 21 & 27 \\\hline 16 & 19 & 24 \\\hline 29 & 25 & 31 \\\hline & 28 & 23 \\\hline & 19 & \\\hline\end{array}
 Alloy 1Â
15
23
16
29
​
 Alloy 2Â
17
21
19
25
28
19
​
 Alloy 3Â
25
27
24
31
23
​
​
Question 5
Essay
The following statistics were calculated based on samples drawn from four normal populations.
 TreatmentÂ
 StatisticÂ
1
2
3
4
n
j
4
7
5
5
∑
x
j
52
69
71
61
∑
x
j
2
753
798
1248
912
\begin{array} { | c | c | c | c | c | } \hline \text { Treatment } & & & & \\\hline \text { Statistic } & 1 & 2 & 3 & 4 \\\hline n _ { j } & 4 & 7 & 5 & 5 \\\hline \sum x _ { j } & 52 & 69 & 71 & 61 \\\hline \sum x _ { j } ^ { 2 } & 753 & 798 & 1248 & 912 \\\hline\end{array}
 TreatmentÂ
 StatisticÂ
n
j
​
∑
x
j
​
∑
x
j
2
​
​
1
4
52
753
​
2
7
69
798
​
3
5
71
1248
​
4
5
61
912
​
​
Test at the 5% level of significance to determine whether differences exist among the population means.
Question 6
Essay
In a completely randomised design, 15 experimental units were assigned to each of four treatments. Fill in the blanks (identified by asterisks) in the partial ANOVA table shown below.
 Source of VariationÂ
 SSÂ
d
f
M
S
F
 TreatmentsÂ
∗
∗
240
∗
 ErrorÂ
∗
∗
∗
 TotalÂ
2512
∗
\begin{array} { | l | c | c | c | c | } \hline \text { Source of Variation } & \text { SS } & d f & M S & F \\\hline \text { Treatments } & * & * & 240 & * \\\hline \text { Error } & * & * & * & \\\hline \text { Total } & 2512 & * & & \\\hline\end{array}
 Source of VariationÂ
 TreatmentsÂ
 ErrorÂ
 TotalÂ
​
 SSÂ
∗
∗
2512
​
df
∗
∗
∗
​
MS
240
∗
​
F
∗
​
​
Question 7
Essay
A partial ANOVA table in a randomised block design is shown below.
 Source of VariationÂ
 SSÂ
d
f
M
S
F
 TreatmentsÂ
∗
3
∗
∗
 BlocksÂ
1256
2
∗
∗
 ErrorÂ
∗
∗
67.67
 TotalÂ
2922
11
\begin{array} { | l | c | c | c | c | } \hline \text { Source of Variation } & \text { SS } & d f & M S & F \\\hline \text { Treatments } & * & 3 & * & * \\\hline \text { Blocks } & 1256 & 2 & * & * \\\hline \text { Error } & * & * & 67.67 & \\\hline \text { Total } & 2922 & 11 & & \\\hline\end{array}
 Source of VariationÂ
 TreatmentsÂ
 BlocksÂ
 ErrorÂ
 TotalÂ
​
 SSÂ
∗
1256
∗
2922
​
df
3
2
∗
11
​
MS
∗
∗
67.67
​
F
∗
∗
​
​
Fill in the missing values (identified by asterisks) in the above ANOVA table.
Question 8
Essay
The following statistics were calculated based on samples drawn from three normal populations:
 TreatmentÂ
 StatisticÂ
1
2
3
n
10
10
10
x
ˉ
95
86
92
s
10
12
15
\begin{array} { | c | c c c | } \hline & { \text { Treatment } } \\\hline \text { Statistic } & 1 & 2 & 3 \\\hline n & 10 & 10 & 10 \\\hline \bar { x } & 95 & 86 & 92 \\\hline s & 10 & 12 & 15 \\\hline\end{array}
 StatisticÂ
n
x
ˉ
s
​
 TreatmentÂ
1
10
95
10
​
2
10
86
12
​
3
10
92
15
​
​
Set up the ANOVA table and test at the 5% level of significance to determine whether differences exist among the population means.
Question 9
Multiple Choice
One-way ANOVA is performed on independent samples taken from three normally distributed populations with equal variances. The following summary statistics are calculated:
n
1
=
n _ { 1 } =
n
1
​
=
6,
x
ˉ
1
=
\bar { x } _ { 1 } =
x
ˉ
1
​
=
50,
s
1
=
s _ { 1 } =
s
1
​
=
5.2.
n
2
=
n _ { 2 } =
n
2
​
=
8,
x
ˉ
2
=
\bar { x } _ { 2 } =
x
ˉ
2
​
=
55,
S
2
=
S _ { 2 } =
S
2
​
=
4.9 .
n
3
=
n _ { 3 } =
n
3
​
=
6,
x
ˉ
3
=
\bar { x } _ { 3 } =
x
ˉ
3
​
=
51,
s
3
=
s _ { 3 } =
s
3
​
=
5.4. The grand mean equals:
Question 10
Multiple Choice
In single-factor analysis of variance, if large differences exist among the sample means, it is then reasonable to:
Question 11
True/False
The sum of squares for treatments stands for the between-treatments variation.
Question 12
Multiple Choice
One-way ANOVA is performed on independent samples taken from three normally distributed populations with equal variances. The following summary statistics were calculated:
n
1
=
n _ { 1 } =
n
1
​
=
7,
x
ˉ
1
=
\bar { x } _ { 1 } =
x
ˉ
1
​
=
65,
s
1
=
s _ { 1 } =
s
1
​
=
4.2.
n
2
=
n _ { 2 } =
n
2
​
=
8,
x
ˉ
2
=
\bar { x } _ { 2 } =
x
ˉ
2
​
=
59,
S
2
=
S _ { 2 } =
S
2
​
=
4.9.
n
3
=
n _ { 3 } =
n
3
​
=
9,
x
ˉ
3
=
\bar { x } _ { 3 } =
x
ˉ
3
​
=
63,
s
3
=
s _ { 3 } =
s
3
​
=
4.6. The value of the test statistics, F, equals:
Question 13
Multiple Choice
Which of the following is true of the F-distribution?
Question 14
True/False
The randomised block design is also called the two-way analysis of variance.
Question 15
True/False
Given the significance level 0.025, the F-value for the numbers of degrees of freedom d.f. = (4, 8) is 5.05.
Question 16
Essay
A recent college graduate is in the process of deciding which one of three US graduate schools he should apply to. He decides to judge the quality of the schools on the basis of the Graduate Management Admission Test (GMAT) scores of those who are accepted into the school. A random sample of six students in each school produced the following GMAT scores.
\quad
\quad
\quad
\quad
\quad
 GMAT ScoresÂ
\text { GMAT Scores }
 GMAT ScoresÂ
 School 1Â
 School 2Â
 School 3Â
650
510
590
620
550
510
630
700
520
580
630
500
710
600
490
690
650
530
\begin{array}{|c|c|c|}\hline \text { School 1 } & \text { School 2 } & \text { School 3 } \\\hline 650 & 510 & 590 \\\hline 620 & 550 & 510 \\\hline 630 & 700 & 520 \\\hline 580 & 630 & 500 \\\hline 710 & 600 & 490 \\\hline 690 & 650 & 530 \\\hline\end{array}
 School 1Â
650
620
630
580
710
690
​
 School 2Â
510
550
700
630
600
650
​
 School 3Â
590
510
520
500
490
530
​
​
Use Tukey's method with
α
\alpha
α
=0.05 to determine which population means differ.
Question 17
Multiple Choice
A survey will be conducted to compare the grade point averages of US high-school students from four different school districts. Students are to be randomly selected from each of the four districts and their grade point averages recorded. The ANOVA model most likely to fit this situation is:
Question 18
True/False
The number of degrees of freedom for the numerator or MST is 3 and that for the denominator or MSE is 18. The total number of observations in the completely randomised design must equal 22.
Question 19
True/False
The F-test of the randomised block design of the analysis of variance has the same requirements as the independent-samples design; that is, the random variable must be normally distributed and the population variances must be equal.