If$\vec{F}=-4 \vec{G}$ And S Is an Oriented Surface, Then$\int _ { S } \vec { F } \cdot \vec { d A } = - 4 \int _ { S } \vec { G } \cdot \vec { d A }$

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The Answer of If$\vec{F}=-4 \vec{G}$ And S Is an Oriented Surface, Then$\int _ { S } \vec { F } \cdot \vec { d A } = - 4 \int _ { S } \vec { G } \cdot \vec { d A }$

If $\vec{F}=-4 \vec{G}$ And S Is an Oriented Surface, Then $\int _ { S } \vec { F } \cdot \vec { d A } = - 4 \int _ { S } \vec { G } \cdot \vec { d A }$

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If F⃗=−4G⃗\vec{F}=-4 \vec{G}F=−4G And S Is an Oriented Surface, Then ∫SF⃗⋅dA⃗=−4∫SG⃗⋅dA⃗\int _ { S } \vec { F } \cdot \vec { d A } = - 4 \int _ { S } \vec { G } \cdot \vec { d A }∫S​F⋅dA=−4∫S​G⋅dA

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If $\vec{F}=-4 \vec{G}$ And S Is an Oriented Surface, Then $\int _ { S } \vec { F } \cdot \vec { d A } = - 4 \int _ { S } \vec { G } \cdot \vec { d A }$

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