Suppose $\int_{a}^{b} g(x) d x=6$ $\int_{a}^{b}(g(x))^{2} d x=8$ $\int_{a}^{b} h(x) d x=0$

Short Answer

Suppose $\int_{a}^{b} g(x) d x=6$ , $\int_{a}^{b}(g(x))^{2} d x=8$ , $\int_{a}^{b} h(x) d x=0$ , and $\int_{a}^{b}(h(x))^{2} d x=2$ .Find $\int_{a}^{b}\left((g(x))^{2}+(h(x))^{2}\right) d x$ .