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Determine If the Vector P Is in Span S or Aff

Question 19

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Determine if the vector p is in Span S or aff S.
-  Let v1=[2132],v2=[3104],v3=[5412],p=[5353], and S={v1,v2,v3}. It can be shown that S is linearly \text { Let } \mathbf{v}_{1}=\left[\begin{array}{r}2 \\1 \\3 \\-2\end{array}\right], \mathbf{v}_{2}=\left[\begin{array}{r}3 \\-1 \\0 \\4\end{array}\right], \mathbf{v}_{3}=\left[\begin{array}{r}5 \\4 \\-1 \\-2\end{array}\right], p=\left[\begin{array}{r}5 \\-3 \\5 \\3\end{array}\right] \text {, and } \mathrm{S}=\left\{\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}\right\} \text {. It can be shown that } \mathrm{S} \text { is linearly } independent.


A) p\mathbf { p } \in span SS and p\mathbf { p } \notin aff SS
B) pspanS\mathbf { p } \notin \operatorname { span } S and p\mathbf { p } \in aff SS
C) pspanS\mathbf { p } \in \operatorname { span } S and p\mathbf { p } \in aff SS
D) pspanS\mathbf { p } \notin \operatorname { span } S and p\mathbf { p } \notin aff SS

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