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The Graph of the Equation Is a Circle $(x-4)^{2}+y^{2}=9$ A) Center $( 0 , - 4 )$

Question 70

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $(x-4) ^{2}+y^{2}=9$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x-4) ^{2}+y^{2}=9 A) center ( 0 , - 4 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( - 4,0 ) ; radius = 3 D) center ( 4,0 ) ; radius = 3$

A) center $( 0 , - 4 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x-4) ^{2}+y^{2}=9 A) center ( 0 , - 4 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( - 4,0 ) ; radius = 3 D) center ( 4,0 ) ; radius = 3$
B) center $( 0,4 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x-4) ^{2}+y^{2}=9 A) center ( 0 , - 4 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( - 4,0 ) ; radius = 3 D) center ( 4,0 ) ; radius = 3$
C) center $( - 4,0 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x-4) ^{2}+y^{2}=9 A) center ( 0 , - 4 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( - 4,0 ) ; radius = 3 D) center ( 4,0 ) ; radius = 3$
D) center $( 4,0 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x-4) ^{2}+y^{2}=9 A) center ( 0 , - 4 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( - 4,0 ) ; radius = 3 D) center ( 4,0 ) ; radius = 3$

The Graph of the Equation Is a Circle (x−4)2+y2=9(x-4)^{2}+y^{2}=9(x−4)2+y2=9 A) Center (0,−4)( 0 , - 4 )(0,−4)

Multiple Choice

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The Graph of the Equation Is a Circle $(x-4)^{2}+y^{2}=9$ A) Center $( 0 , - 4 )$

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