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The Graph of the Equation Is a Circle $y^{2}+x^{2}+6 x=0$ A) Center

Question 71

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $y^{2}+x^{2}+6 x=0$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - y^{2}+x^{2}+6 x=0 A) center ( 0,3 ) ; radius = 3 B) center ( - 0 , - 3 ) ; radius = 3 C) center ( 3,0 ) ; radius = 3 D) center ( - 3 , - 0 ) ; radius = 3$

A) center $( 0,3 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - y^{2}+x^{2}+6 x=0 A) center ( 0,3 ) ; radius = 3 B) center ( - 0 , - 3 ) ; radius = 3 C) center ( 3,0 ) ; radius = 3 D) center ( - 3 , - 0 ) ; radius = 3$
B) center $( - 0 , - 3 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - y^{2}+x^{2}+6 x=0 A) center ( 0,3 ) ; radius = 3 B) center ( - 0 , - 3 ) ; radius = 3 C) center ( 3,0 ) ; radius = 3 D) center ( - 3 , - 0 ) ; radius = 3$
C) center $( 3,0 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - y^{2}+x^{2}+6 x=0 A) center ( 0,3 ) ; radius = 3 B) center ( - 0 , - 3 ) ; radius = 3 C) center ( 3,0 ) ; radius = 3 D) center ( - 3 , - 0 ) ; radius = 3$
D) center $( - 3 , - 0 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - y^{2}+x^{2}+6 x=0 A) center ( 0,3 ) ; radius = 3 B) center ( - 0 , - 3 ) ; radius = 3 C) center ( 3,0 ) ; radius = 3 D) center ( - 3 , - 0 ) ; radius = 3$

The Graph of the Equation Is a Circle y2+x2+6x=0y^{2}+x^{2}+6 x=0y2+x2+6x=0 A) Center

Multiple Choice

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The Graph of the Equation Is a Circle $y^{2}+x^{2}+6 x=0$ A) Center

Correct Answer:
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