Find the inverse, if it exists, for the matrix.
-

\left[ \begin{array} { r r r r } 6 & - 3 & 4 & - 3 \\6 & - 2 & - 3 & - 2 \\12 & - 5 & 1 & - 5 \\0 & - 6 & 8 & 0\end{array} \right]

A)

\left[ \begin{array} { r r r r } 1 & 0 & 0 & - \frac { 1 } { 2 } \\0 & 1 & 0 & - \frac { 4 } { 17 } \\0 & 0 & 1 & - \frac { 3 } { 17 } \\0 & 0 & 0 & 0\end{array} \right]

B) The inverse does not exist.

C)

\left[ \begin{array} { c c c c } \frac { 1 } { 6 } & - \frac { 1 } { 3 } & \frac { 1 } { 4 } & - \frac { 1 } { 3 } \\\frac { 1 } { 6 } & - \frac { 1 } { 2 } & - 3 & - \frac { 1 } { 2 } \\\frac { 1 } { 12 } & - \frac { 1 } { 5 } & 1 & - \frac { 1 } { 5 } \\0 & - \frac { 1 } { 6 } & \frac { 1 } { 8 } & 0\end{array} \right]

D)

\left[ \begin{array} { r r r r } \frac { 1 } { 6 } & - \frac { 1 } { 3 } & \frac { 1 } { 4 } & - \frac { 1 } { 3 } \\\frac { 1 } { 6 } & - \frac { 1 } { 2 } & - \frac { 1 } { 3 } & - \frac { 1 } { 2 } \\\frac { 1 } { 12 } & - \frac { 1 } { 5 } & 1 & - \frac { 1 } { 5 } \\0 & - \frac { 1 } { 6 } & \frac { 1 } { 8 } & 0\end{array} \right]

Use a Graphing Calculator to Express Solutions with Approximations to the Nearest

Multiple Choice