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For the Equation, Determine the Constants a and B That x3x2=Ax+Bx2\frac { x - 3 } { x ^ { 2 } } = \frac { A } { x } + \frac { B } { x ^ { 2 } }

Question 467

Multiple Choice

For the equation, determine the constants A and B that make the equation an identity.
- x3x2=Ax+Bx2\frac { x - 3 } { x ^ { 2 } } = \frac { A } { x } + \frac { B } { x ^ { 2 } }


A) A=3,B=1A = - 3 , B = 1
B) A=3, B=1\mathrm { A } = 3 , \mathrm {~B} = 1
C) A=1, B=3\mathrm { A } = 1 , \mathrm {~B} = - 3
D) A=1,B=3A = 1 , B = 3

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