Solve the Equation on the Interval $0 \leq \theta < 2 \pi .$

Multiple Choice

Solve the equation on the interval $0 \leq \theta < 2 \pi .$
- $2 \sin ^ { 2 } \theta = \sin \theta$

A) $\frac { \pi } { 3 } , \frac { 2 \pi } { 3 }$
B) $\frac { \pi } { 6 } , \frac { 5 \pi } { 6 }$
C) $\frac { \pi } { 2 } , \frac { 3 \pi } { 2 } , \frac { \pi } { 3 } , \frac { 2 \pi } { 3 }$
D) $0 , \pi , \frac { \pi } { 6 } , \frac { 5 \pi } { 6 }$