Solve the Equation on the Interval $$0 \leq \theta < 2 \pi \text {. }$$

Multiple Choice

Solve the equation on the interval $$0 \leq \theta < 2 \pi \text {. }$$
- $\sin \theta + \sqrt { 3 } \cos \theta = - 1$

A) $\frac { 3 \pi } { 2 } , \frac { 5 \pi } { 6 }$

B) $0 , \frac { 2 \pi } { 3 }$

C) $\frac { \pi } { 2 } , \frac { 7 \pi } { 6 }$

D) $\frac { 3 \pi } { 2 } , \frac { \pi } { 6 }$