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Solve the Problem h=414+53sin2πx365h = \frac { 41 } { 4 } + \frac { 5 } { 3 } \sin \frac { 2 \pi x } { 365 }

Question 110

Short Answer

Solve the problem.
-The seasonal variation in the length of daylight can be represented by a sine function. For example, the daily
number of hours of daylight in a certain city in the U.S. can be given b h=414+53sin2πx365h = \frac { 41 } { 4 } + \frac { 5 } { 3 } \sin \frac { 2 \pi x } { 365 } , where x is the
number of days after March 21 ( disregarding leap year). On what day(s) will there be about 10 hours of
daylight?

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191 days after March 21 and 35...

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