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Solve the Equation for Solutions in the Interval [0, 2 [0,2π).[ 0,2 \pi ) .

Question 161

Multiple Choice

Solve the equation for solutions in the interval [0, 2 [0,2π) .[ 0,2 \pi ) .
- sinxcosx=12\sin x \cos x = \frac { 1 } { 2 }


A) {0}\{ 0 \}
B) {π4,5π4}\left\{ \frac { \pi } { 4 } , \frac { 5 \pi } { 4 } \right\}
C) {0,π4,π,5π4}\left\{ 0 , \frac { \pi } { 4 } , \pi , \frac { 5 \pi } { 4 } \right\}
D) {π12,π6,2π3,7π12,7π6,13π12,5π3}\left\{ \frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } \right\}

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