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Solve the Equation for Solutions in the Interval [0°, 360°) cos2θ=32\cos 2 \theta = \frac { \sqrt { 3 } } { 2 }

Question 160

Multiple Choice

Solve the equation for solutions in the interval [0°, 360°) . Round to the nearest degree.
- cos2θ=32\cos 2 \theta = \frac { \sqrt { 3 } } { 2 }


A) {105,165,285,345}\left\{ 105 ^ { \circ } , 165 ^ { \circ } , 285 ^ { \circ } , 345 ^ { \circ } \right\}
B) {0,120,180,240}\left\{ 0 ^ { \circ } , 120 ^ { \circ } , 180 ^ { \circ } , 240 ^ { \circ } \right\}
C) {30,90,150,270}\left\{ 30 ^ { \circ } , 90 ^ { \circ } , 150 ^ { \circ } , 270 ^ { \circ } \right\}
D) {15,165,195,345}\left\{ 15 ^ { \circ } , 165 ^ { \circ } , 195 ^ { \circ } , 345 ^ { \circ } \right\}

Correct Answer:

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