Write the expression in terms of sine and cosine, and simplify so that no quotients appear in the final expression.
-The power dissipated in an electric circuit is given by the expression

\mathrm { P } = \mathrm { RI } ^ { 2 }

, where

\mathrm { R }

is the resistance of the circuit and

I

is the current through the circuit. For a sinusoidal alternating current, the current might be represented by the relation

\mathrm { I } = \mathrm { A } \sin ( 2 \pi \mathrm { ft } )

, where

\mathrm { A }

is the amplitude,

\mathrm { f }

is the frequency, and

t

is time. Write an expression for

P

involving the sine function, and use a fundamental identity to write

P

in terms of the cosine function.
A)

P = R A ^ { 2 } \sin ^ { 2 } ( 2 \pi f t ) ; P = - R A ^ { 2 } \cos ^ { 2 } ( 2 \pi f t )

P = R A \sin ^ { 2 } ( 2 \pi f t ) ; P = R A - \cos ^ { 2 } ( 2 \pi f t )

P = R A ^ { 2 } \sin ^ { 2 } ( 2 \pi f \mathrm { ft } ) ; P = R A ^ { 2 } - R A ^ { 2 } \cos ^ { 2 } ( 2 \pi f t )

P = R A \sin ^ { 2 } ( 2 \pi f \mathrm { ft } ) ; P = R A - R A \cos ^ { 2 } ( 2 \pi f t )

Perform the Transformation sec⁡x\sec xsecx In Terms Of tan⁡x\tan xtanx A) ±tan⁡2x+1tan⁡x\frac { \pm \sqrt { \tan ^ { 2 } x + 1 } } { \tan x }tanx±tan2x+1​​

Multiple Choice

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Perform the Transformation $\sec x$ In Terms Of $\tan x$
A) $\frac { \pm \sqrt { \tan ^ { 2 } x + 1 } } { \tan x }$

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