Solve the Initial Value Problem for X as a Function $$\left( t ^ { 2 } - 5 t + 6 \right) \frac { d x } { d t } = 1 \quad ( t > 3 ) , x ( 4 ) = 0$$

Multiple Choice

Solve the initial value problem for x as a function of t.
- $$\left( t ^ { 2 } - 5 t + 6 \right) \frac { d x } { d t } = 1 \quad ( t > 3 ) , x ( 4 ) = 0$$

A) $x = - \ln | t - 2 | + \ln | t - 3 | + \ln 2$
B) $x = - \ln | t - 2 | + \ln | t - 3 | + 2$
C) $x = - \ln | t - 2 | + \frac { 1 } { t - 3 } + \ln 2$
D) $x = \ln | t - 2 | - \ln | t - 3 | + \ln 2$