Solve the Initial Value Problem for X as a Function $$\left( t ^ { 2 } + 2 t \right) \frac { d x } { d t } = 2 x + 8 , x ( 1 ) = 1$$

Multiple Choice

Solve the initial value problem for x as a function of t.
- $$\left( t ^ { 2 } + 2 t \right) \frac { d x } { d t } = 2 x + 8 , x ( 1 ) = 1$$

A) $x = 15 \ln \left| \frac { t } { t + 2 } \right| - 4$
B) $x = \frac { 14 t } { t + 2 } - 4$
C) $x = \frac { 15 t } { t + 2 } - 4$
D) $x = 15 t + \ln | t + 2 | - 4$