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Solve the Problem (4,1)( - 4,1 ) Whose Length Integral 1y21 \leq y \leq 2

Question 141

Multiple Choice

Solve the problem.
-Find a curve through the point (4,1) ( - 4,1 ) whose length integral, 1y21 \leq y \leq 2 , is L=121+4y3dyL = \int _ { 1 } ^ { 2 } \sqrt { 1 + \frac { 4 } { y ^ { 3 } } } \mathrm { dy } .


A) x=2yx = \frac { 2 } { \sqrt { y } }
B) x=4yx = \frac { - 4 } { \sqrt { y } }
C) x=4y5/2x = - 4 y ^ { 5 / 2 }
D) x=4yx = - 4 \sqrt { y }

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