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Set Up an Integral for the Area of the Surface y=cotx,0xπ/4;xy = \cot x , 0 \leq x \leq \pi / 4 ; x

Question 214

Multiple Choice

Set up an integral for the area of the surface generated by revolving the given curve about the indicated axis.
- y=cotx,0xπ/4;xy = \cot x , 0 \leq x \leq \pi / 4 ; x -axis


A) 0π/4cscx1+cotxdx\int _ { 0 } ^ { \pi / 4 } \csc x \sqrt { 1 + \cot x } d x
B) 0π/4cotx1+csc4xdx\int _ { 0 } ^ { \pi / 4 } \cot x \sqrt { 1 + \csc ^ { 4 } x } d x
C) 2π0π/4cotx1+csc4xdx2 \pi \int _ { 0 } ^ { \pi / 4 } \cot x \sqrt { 1 + \csc ^ { 4 } x } d x
D) 2π0π/4cscx1+cotxdx2 \pi \int _ { 0 } ^ { \pi / 4 } \csc x \sqrt { 1 + \cot x } d x

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