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Find the Moment or Center of Mass of the Wire x2+y2=25x ^ { 2 } + y ^ { 2 } = 25

Question 208

Multiple Choice

Find the moment or center of mass of the wire, as indicated.
-Find the center of mass of a wire that lies along the first-quadrant portion of the circle x2+y2=25x ^ { 2 } + y ^ { 2 } = 25 if the density of the wire is δ=5sinθ\delta = 5 \sin \theta .


A) xˉ=0,yˉ=58π\bar { x } = 0 , \bar { y } = \frac { 5 } { 8 } \pi
B) xˉ=5π,yˉ=5π\bar { x } = 5 \pi , \bar { y } = 5 \pi
C) xˉ=54π,yˉ=54π\bar { x } = \frac { 5 } { 4 } \pi , \bar { y } = \frac { 5 } { 4 } \pi
D) xˉ=58π,yˉ=58π\bar { x } = \frac { 5 } { 8 } \pi , \bar { y } = \frac { 5 } { 8 } \pi

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