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Solve the Problem PP


A) y=2x+1+2y = \sqrt { 2 } x + 1 + \sqrt { 2 }

Question 368

Multiple Choice

Solve the problem.
-Find an equation for the tangent to the curve at PP .
 Solve the problem. -Find an equation for the tangent to the curve at  P .    A)   y = \sqrt { 2 } x + 1 + \sqrt { 2 }  B)   y = - \sqrt { 2 } x + \frac { \pi \sqrt { 2 } } { 4 } - 1 - \sqrt { 2 }  C)   y = \sqrt { 2 } x - \frac { \pi \sqrt { 2 } } { 4 } + 1 + \sqrt { 2 }  D)   y = - \sqrt { 2 } x - 1 - \sqrt { 2 }


A) y=2x+1+2y = \sqrt { 2 } x + 1 + \sqrt { 2 }
B) y=2x+π2412y = - \sqrt { 2 } x + \frac { \pi \sqrt { 2 } } { 4 } - 1 - \sqrt { 2 }
C) y=2xπ24+1+2y = \sqrt { 2 } x - \frac { \pi \sqrt { 2 } } { 4 } + 1 + \sqrt { 2 }
D) y=2x12y = - \sqrt { 2 } x - 1 - \sqrt { 2 }

Correct Answer:

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