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Find the Derivative of Y with Respect to the Independent y=log9(x24x+1)y = \log 9 \left( \frac { x ^ { 2 } } { 4 \sqrt { x + 1 } } \right)

Question 373

Multiple Choice

Find the derivative of y with respect to the independent variable.
- y=log9(x24x+1) y = \log 9 \left( \frac { x ^ { 2 } } { 4 \sqrt { x + 1 } } \right)


A) 1ln9(4x+1x2) \frac { 1 } { \ln 9 } \left( \frac { 4 \sqrt { x + 1 } } { x ^ { 2 } } \right)
B) 1ln9(2x212x+1) \frac { 1 } { \ln 9 } \left( \frac { 2 } { x ^ { 2 } } - \frac { 1 } { 2 \sqrt { x + 1 } } \right)
C) e9(4x+1x2) \mathrm { e } ^ { 9 } \left( \frac { 4 \sqrt { \mathrm { x } + 1 } } { \mathrm { x } ^ { 2 } } \right)
D) 1ln9(2x12(x+1) ) \frac { 1 } { \ln 9 } \left( \frac { 2 } { x } - \frac { 1 } { 2 ( x + 1 ) } \right)

Correct Answer:

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