Solved

Use the Given Transformation to Evaluate the Integral Where RR Is the Interior of the Ellipsoid

Question 145

Multiple Choice

Use the given transformation to evaluate the integral.
- x=4u,y=5v,z=7w;(x216+y225+z249) πdxdy\begin{array} { l } x = 4 u , y = 5 v , z = 7 w ; \\\quad \iiint \left( \frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 25 } + \frac { z ^ { 2 } } { 49 } \right) ^ { \pi } d x d y\end{array}
where RR is the interior of the ellipsoid x216+y225+z249=1\frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 25 } + \frac { z ^ { 2 } } { 49 } = 1


A) 280ππ+1\frac { 280 \pi } { \pi + 1 }
B) 560ππ+2\frac { 560 \pi } { \pi + 2 }
C) 560ππ+3\frac { 560 \pi } { \pi + 3 }
D) 560ππ+1\frac { 560 \pi } { \pi + 1 }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions