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    Mathematics
  3. Study Set
    Thomas Calculus Early Transcendentals
  4. Exam
    Exam 15: Partial Derivatives
  5. Question
    Sketch the Surface Z = F(x,y)\[f ( x , y ) = - \sqrt { x ^ { 2 } + y ^ { 2 } }\]
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Sketch the Surface Z = F(x,y) f(x,y)=−x2+y2f ( x , y ) = - \sqrt { x ^ { 2 } + y ^ { 2 } }f(x,y)=−x2+y2​

Question 265

Question 265

Multiple Choice

Sketch the surface z = f(x,y) .
- f(x,y) =−x2+y2f ( x , y ) = - \sqrt { x ^ { 2 } + y ^ { 2 } }f(x,y) =−x2+y2​


A)
 Sketch the surface z = f(x,y) . - f ( x , y )  = - \sqrt { x ^ { 2 } + y ^ { 2 } }   A)    B)    C)    D)
B)
 Sketch the surface z = f(x,y) . - f ( x , y )  = - \sqrt { x ^ { 2 } + y ^ { 2 } }   A)    B)    C)    D)
C)
 Sketch the surface z = f(x,y) . - f ( x , y )  = - \sqrt { x ^ { 2 } + y ^ { 2 } }   A)    B)    C)    D)
D)
 Sketch the surface z = f(x,y) . - f ( x , y )  = - \sqrt { x ^ { 2 } + y ^ { 2 } }   A)    B)    C)    D)

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