Solve the Problem $x ^ { 2 } + y ^ { 2 } + 2 z = 4$

Multiple Choice

Solve the problem.
-Find the point on the curve of intersection of the paraboloid $x ^ { 2 } + y ^ { 2 } + 2 z = 4$ and the plane $x - y + 2 z = 0$ that is farthest from the origin.

A) (-2, 2, 2)
B) (2, -2, -2)
C) (2, -2, 2)
D) (-2, -2, 2)