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Find an Equation for the Line Tangent to the Curve x=sint,y=6sint,t=π3x = \sin t , y = 6 \sin t , t = \frac { \pi } { 3 }

Question 68

Multiple Choice

Find an equation for the line tangent to the curve at the point defined by the given value of t.
- x=sint,y=6sint,t=π3x = \sin t , y = 6 \sin t , t = \frac { \pi } { 3 }


A) y=6x+63y = - 6 x + 6 \sqrt { 3 }
B) y=6xy = 6 x
C) y=6x63y = 6 x - 6 \sqrt { 3 }
D) y=6x+32y = 6 x + \frac { \sqrt { 3 } } { 2 }

Correct Answer:

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