Solved

The Eccentricity Is Given of a Conic Section with One e=13,y=5e = \frac { 1 } { 3 } , y = 5

Question 69

Multiple Choice

The eccentricity is given of a conic section with one focus at the origin, along with the directrix corresponding to that focus. Find a polar equation for the conic section.
- e=13,y=5e = \frac { 1 } { 3 } , y = 5


A) r=53sinθr = \frac { 5 } { 3 - \sin \theta }
B) r=53+sinθr = \frac { 5 } { 3 + \sin \theta }
C) r=51+3cosθr = \frac { 5 } { 1 + 3 \cos \theta }
D) r=53+cosθr = \frac { 5 } { 3 + \cos \theta }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions