Solved

Find the Standard Form of the Equation of the Hyperbola (y1)24(x2)225=1\frac { ( y - 1 ) ^ { 2 } } { 4 } - \frac { ( x - 2 ) ^ { 2 } } { 25 } = 1

Question 2

Multiple Choice

Find the standard form of the equation of the hyperbola.
- Find the standard form of the equation of the hyperbola. -  A)   \frac { ( y - 1 )  ^ { 2 } } { 4 } - \frac { ( x - 2 )  ^ { 2 } } { 25 } = 1  B)   \frac { ( y - 1 )  ^ { 2 } } { 25 } - \frac { ( x - 2 )  ^ { 2 } } { 4 } = 1  C)   \frac { ( x - 2 )  ^ { 2 } } { 25 } - \frac { ( y - 1 )  ^ { 2 } } { 4 } = 1  D)   \frac { ( x - 2 )  ^ { 2 } } { 4 } - \frac { ( y - 1 )  ^ { 2 } } { 25 } = 1


A) (y1) 24(x2) 225=1\frac { ( y - 1 ) ^ { 2 } } { 4 } - \frac { ( x - 2 ) ^ { 2 } } { 25 } = 1
B) (y1) 225(x2) 24=1\frac { ( y - 1 ) ^ { 2 } } { 25 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1
C) (x2) 225(y1) 24=1\frac { ( x - 2 ) ^ { 2 } } { 25 } - \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1
D) (x2) 24(y1) 225=1\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 25 } = 1

Correct Answer:

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