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Find the Standard Form of the Equation of the Ellipse (x+2)264+(y+4)216=1\frac { ( x + 2 ) ^ { 2 } } { 64 } + \frac { ( y + 4 ) ^ { 2 } } { 16 } = 1

Question 1

Multiple Choice

Find the standard form of the equation of the ellipse satisfying the given conditions.
-Endpoints of major axis: (-10, -4) and (6, -4) ; endpoints of minor axis: (-2, -8) and (-2, 0)


A) (x+2) 264+(y+4) 216=1\frac { ( x + 2 ) ^ { 2 } } { 64 } + \frac { ( y + 4 ) ^ { 2 } } { 16 } = 1
B) (x+4) 216+(y+2) 264=1\frac { ( x + 4 ) ^ { 2 } } { 16 } + \frac { ( y + 2 ) ^ { 2 } } { 64 } = 1
C) (x2) 264+(y4) 216=0\frac { ( x - 2 ) ^ { 2 } } { 64 } + \frac { ( y - 4 ) ^ { 2 } } { 16 } = 0
D) (x2) 264+(y4) 216=1\frac { ( x - 2 ) ^ { 2 } } { 64 } + \frac { ( y - 4 ) ^ { 2 } } { 16 } = 1

Correct Answer:

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