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Use the Center, Vertices, and Asymptotes to Graph the Hyperbola $\frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1$

Question 56

Multiple Choice

Use the center, vertices, and asymptotes to graph the hyperbola.
- $\frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1$
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1 A) B) C)$

A)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1 A) B) C)$
B)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1 A) B) C)$
C)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1 A) B) C)$

Use the Center, Vertices, and Asymptotes to Graph the Hyperbola (x+1)24−(y−1)216=1\frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 14(x+1)2​−16(y−1)2​=1

Multiple Choice

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Use the Center, Vertices, and Asymptotes to Graph the Hyperbola $\frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1$

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