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 The length of a rectangle is 5t+5 and its height is t4, where t is time in seconds and \text { The length of a rectangle is } 5 t + 5 \text { and its height is } t ^ { 4 } \text {, where } t \text { is time in seconds and }

Question 79

Multiple Choice

 The length of a rectangle is 5t+5 and its height is t4, where t is time in seconds and \text { The length of a rectangle is } 5 t + 5 \text { and its height is } t ^ { 4 } \text {, where } t \text { is time in seconds and } the dimensions are in inches. Find the rate of change of area, A, with respect to time.


A) dAdt=t4(20+25t) \frac { d A } { d t } = t ^ { 4 } ( 20 + 25 t ) square inches/second
B) dAdt=t4(15+25t) \frac { d A } { d t } = t ^ { 4 } ( 15 + 25 t ) square inches/second
C) dAdt=t3(20+20t) \frac { d A } { d t } = t ^ { 3 } ( 20 + 20 t ) square inches/second
D) dAdt=t3(20+25t) \frac { d A } { d t } = t ^ { 3 } ( 20 + 25 t ) square inches/second
E) dAdt=t3(25t+5) \frac { d A } { d t } = t ^ { 3 } ( 25 t + 5 ) square inches/second

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