Solved

The Force  F\ { F } (In Newtons) of a Hydraulic Cylinder in a Press Is

Question 130

Multiple Choice

The Force  F\ { F } (in newtons) of a hydraulic cylinder in a press is proportional to the square of secx\sec x where xx is the distance (in meters) that the cylinder is extended in its cycle. The domain of FF is [0,π3]\left[ 0 , \frac { \pi } { 3 } \right] and F(0) =150F ( 0 ) = 150 . Find FF as a function of xx .


A) F(x) =150sec2xF ( x ) = 150 \sec ^ { 2 } x
B) F(x) =150+sec2xF ( x ) = 150 + \sec ^ { 2 } x
C) F(x) =300sec2xF ( x ) = 300 \sec ^ { 2 } x
D) F(x) =sec2x+1F ( x ) = \sec ^ { 2 } x + 1
E) F(x) =75sec2xF ( x ) = 75 \sec ^ { 2 } x

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions