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 Solve the first-order linear differential equation dydx=(y1)sin(2x)\text { Solve the first-order linear differential equation } \frac { d y } { d x } = ( y - 1 ) \sin ( 2 x ) \text {. }

Question 49

Multiple Choice

 Solve the first-order linear differential equation dydx=(y1) sin(2x) \text { Solve the first-order linear differential equation } \frac { d y } { d x } = ( y - 1 ) \sin ( 2 x ) \text {. }


A) y=1+Cesin(2x) y = 1 + C e ^ { \sin ( 2 x ) }
B) y=1+Cecos(2x) 2y = 1 + C e ^ -{ \frac { \cos ( 2 x ) } { 2 } }
C) y=1+Cesin(2x) 2y = 1 + C e ^ { \frac { \sin ( 2 x ) } { 2 } }
D) y=1+Cesin(2x) 2y = 1 + C e ^- { \frac { \sin ( 2 x ) } { 2 } }
E) y=1+Cecos(2x) y = 1 + C e ^ { \cos ( 2 x ) }

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