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Find the Fourth Degree Maclaurin Polynomial for the Function f(x)=1x+4f ( x ) = \frac { 1 } { x + 4 }

Question 141

Multiple Choice

Find the fourth degree Maclaurin polynomial for the function. f(x) =1x+4f ( x ) = \frac { 1 } { x + 4 }


A) 14+116x164x2+1256x311024x4\frac { 1 } { 4 } + \frac { 1 } { 16 } x - \frac { 1 } { 64 } x ^ { 2 } + \frac { 1 } { 256 } x ^ { 3 } - \frac { 1 } { 1024 } x ^ { 4 }
B) 14+116x+164x2+1256x3+11024x4\frac { 1 } { 4 } + \frac { 1 } { 16 } x + \frac { 1 } { 64 } x ^ { 2 } + \frac { 1 } { 256 } x ^ { 3 } + \frac { 1 } { 1024 } x ^ { 4 }
C) 4+16x+64x2+256x3+1024x44 + 16 x + 64 x ^ { 2 } + 256 x ^ { 3 } + 1024 x ^ { 4 }
D) 416x+64x2256x3+1024x44 - 16 x + 64 x ^ { 2 } - 256 x ^ { 3 } + 1024 x ^ { 4 }
E) 14116x+164x21256x3+11024x4\frac { 1 } { 4 } - \frac { 1 } { 16 } x + \frac { 1 } { 64 } x ^ { 2 } - \frac { 1 } { 256 } x ^ { 3 } + \frac { 1 } { 1024 } x ^ { 4 }

Correct Answer:

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