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Find the Area of the Surface of the Portion of the Plane

Question 103

Multiple Choice

Find the area of the surface of the portion of the plane z=36x2yz = 3 - 6 x - 2 y
in the first octant.


A) 338\frac { 3 \sqrt { 3 } } { 8 }
B) 3418\frac { 3 \sqrt { 41 } } { 8 }
C) 368\frac { 3 \sqrt { 6 } } { 8 }
D) 8413\frac { 8 \sqrt { 41 } } { 3 }
E) 3841\frac { 3 } { 8 \sqrt { 41 } }

Correct Answer:

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