Find the Absolute Extreme Values of the Function on the Interval

Multiple Choice

Find the absolute extreme values of the function on the interval.
- $$f ( x ) = \tan x , - \frac { \pi } { 4 } \leq x \leq \frac { \pi } { 6 }$$

A) absolute maximum is $\frac { \sqrt { 3 } } { 3 }$ at $x = \frac { \pi } { 6 }$ ; absolute minimum is $- 1$ at $x = - \frac { \pi } { 4 }$
B) absolute maximum is $\frac { \sqrt { 3 } } { 3 }$ at $x = \frac { 2 \pi } { 18 }$ ; absolute minimum is $- 1$ at $x = - \frac { \pi } { 8 }$
C) absolute maximum is $- 1$ at $x = \frac { \pi } { 6 }$ ; absolute minimum is $\frac { \sqrt { 3 } } { 3 }$ at $x = - \frac { \pi } { 4 }$
D) absolute maximum is $\frac { \sqrt { 3 } } { 3 }$ at $x = \frac { \pi } { 6 }$ and $- \frac { \pi } { 4 }$ ; absolute minimum does not exist