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Find the Extreme Values of the Function and Where They y=2xx2+1y = \frac { 2 x } { x ^ { 2 } + 1 }

Question 5

Multiple Choice

Find the extreme values of the function and where they occur.
- y=2xx2+1y = \frac { 2 x } { x ^ { 2 } + 1 }


A) The minimum value is - 1 at x = -1. The maximum value is 1at x = 1.
B) The maximum value is 0 at x = 0.
C) The minimum value is 0 at x = 1. The maximum value is 0 at x = -1.
D) The minimum value is 0 at x = 0.

Correct Answer:

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