Find a formula for the function graphed.
- $Find a formula for the function graphed. - A) f ( x ) = \left\{ \begin{array} { l l } - \frac { 1 } { 2 } x + 1 , & - 8 \leq x \leq - 2 \\ 5 , & - 2 < x \leq 3 \\ x - 6 , & 3 < x \leq 8 \end{array} \quad \right. B) f ( x ) = \left\{ \begin{array} { l l } \frac { 1 } { 2 } x + 1 , & - 8 < x \leq - 2 \\ 5 , & - 2 < x \leq 3 \\ 6 - x , & 3 < x < 8 \end{array} \right. C) f ( x ) = \left\{ \begin{array} { l l } \frac { 1 } { 2 } x + 1 , & - 8 \leq x \leq - 2 \\ 5 , & - 2 < x < 3 \\ 6 - x , & 3 \leq x \leq 8 \end{array} \right. D) f ( x ) = \left\{ \begin{array} { l r } \frac { 1 } { 2 } x + 1 , & - 8 \leq x \leq - 2 \\ 5 , & - 2 < x \leq 3 \\ 6 - x , & 3 < x \leq 8 \end{array} \right.$
A)

f ( x ) = \left\{ \begin{array} { l l } - \frac { 1 } { 2 } x + 1 , & - 8 \leq x \leq - 2 \\ 5 , & - 2 < x \leq 3 \\ x - 6 , & 3 < x \leq 8 \end{array} \quad \right.

f ( x ) = \left\{ \begin{array} { l l } \frac { 1 } { 2 } x + 1 , & - 8 < x \leq - 2 \\ 5 , & - 2 < x \leq 3 \\ 6 - x , & 3 < x < 8 \end{array} \right.

f ( x ) = \left\{ \begin{array} { l l } \frac { 1 } { 2 } x + 1 , & - 8 \leq x \leq - 2 \\ 5 , & - 2 < x < 3 \\ 6 - x , & 3 \leq x \leq 8 \end{array} \right.

f ( x ) = \left\{ \begin{array} { l r } \frac { 1 } { 2 } x + 1 , & - 8 \leq x \leq - 2 \\ 5 , & - 2 < x \leq 3 \\ 6 - x , & 3 < x \leq 8 \end{array} \right.

Find the Domain and Range of the Function F(t)=109tF ( t ) = \frac { 10 } { 9 \sqrt { t } }F(t)=9t​10​

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Find the Domain and Range of the Function $F ( t ) = \frac { 10 } { 9 \sqrt { t } }$

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