Evaluate the Definite Integral $$\int _ { - 1 } ^ { 1 } \frac { \sin x } { 6 + x ^ { 2 } } d x$$

Short Answer

Evaluate the definite integral.
$$\int _ { - 1 } ^ { 1 } \frac { \sin x } { 6 + x ^ { 2 } } d x$$