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Solve the Problem 134 m134 \mathrm {~m} Is 3.03.0 Hours If the Formula P(t)=(12)t/3.0\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.0 }

Question 1

Multiple Choice

Solve the problem.
-The half-life of Cesium 134 m134 \mathrm {~m} is 3.03.0 hours. If the formula P(t) =(12) t/3.0\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.0 } gives the percent (as a decimal) remaining after time t\mathrm { t } (in hours) , sketch P versus t\mathrm { t } .
 Solve the problem. -The half-life of Cesium  134 \mathrm {~m}  is  3.0  hours. If the formula  \mathrm { P } ( \mathrm { t } )  = \left( \frac { 1 } { 2 } \right)  ^ { \mathrm { t } / 3.0 }  gives the percent (as a decimal)  remaining after time  \mathrm { t }  (in hours) , sketch P versus  \mathrm { t } .   A)    B)    C)    D)


A)
 Solve the problem. -The half-life of Cesium  134 \mathrm {~m}  is  3.0  hours. If the formula  \mathrm { P } ( \mathrm { t } )  = \left( \frac { 1 } { 2 } \right)  ^ { \mathrm { t } / 3.0 }  gives the percent (as a decimal)  remaining after time  \mathrm { t }  (in hours) , sketch P versus  \mathrm { t } .   A)    B)    C)    D)
B)
 Solve the problem. -The half-life of Cesium  134 \mathrm {~m}  is  3.0  hours. If the formula  \mathrm { P } ( \mathrm { t } )  = \left( \frac { 1 } { 2 } \right)  ^ { \mathrm { t } / 3.0 }  gives the percent (as a decimal)  remaining after time  \mathrm { t }  (in hours) , sketch P versus  \mathrm { t } .   A)    B)    C)    D)
C)
 Solve the problem. -The half-life of Cesium  134 \mathrm {~m}  is  3.0  hours. If the formula  \mathrm { P } ( \mathrm { t } )  = \left( \frac { 1 } { 2 } \right)  ^ { \mathrm { t } / 3.0 }  gives the percent (as a decimal)  remaining after time  \mathrm { t }  (in hours) , sketch P versus  \mathrm { t } .   A)    B)    C)    D)
D)
 Solve the problem. -The half-life of Cesium  134 \mathrm {~m}  is  3.0  hours. If the formula  \mathrm { P } ( \mathrm { t } )  = \left( \frac { 1 } { 2 } \right)  ^ { \mathrm { t } / 3.0 }  gives the percent (as a decimal)  remaining after time  \mathrm { t }  (in hours) , sketch P versus  \mathrm { t } .   A)    B)    C)    D)

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