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After T Years, the Remaining Mass Y(in Grams) of 16 y=16(12)t/32y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 }

Question 3

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After t years, the remaining mass y(in grams) of 16 grams of a radioactive element whose half-life is 32 years is given by y=16(12) t/32y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 } , for t0t \geq 0 . How much of the initial mass remains after 96 years? Round your answer to two decimal places.


A) 4.00 grams
B) 3.20 grams
C) 4.30 grams
D) 4.90 grams
E) 2.00 grams

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