Solved

The Circuit Shown Below, Let Use Superposition Principle to Find V1V _ { 1 }

Question 13

Essay

the circuit shown below, let Is=3 mA, Vs=6 V,R1=1kΩ,R2=1.2kΩ,R3=1.2kΩ,R4=4kΩ\mathrm { I } _ { \mathrm { s } } = 3 \mathrm {~mA} , \mathrm {~V} _ { \mathrm { s } } = 6 \mathrm {~V} , \mathrm { R } _ { 1 } = 1 \mathrm { k } \Omega , \mathrm { R } _ { 2 } = 1.2 \mathrm { k } \Omega , \mathrm { R } _ { 3 } = 1.2 \mathrm { k } \Omega , \mathrm { R } _ { 4 } = 4 \mathrm { k } \Omega
Use superposition principle to find V1V _ { 1 } .
 the circuit shown below, let  \mathrm { I } _ { \mathrm { s } } = 3 \mathrm {~mA} , \mathrm {~V} _ { \mathrm { s } } = 6 \mathrm {~V} , \mathrm { R } _ { 1 } = 1 \mathrm { k } \Omega , \mathrm { R } _ { 2 } = 1.2 \mathrm { k } \Omega , \mathrm { R } _ { 3 } = 1.2 \mathrm { k } \Omega , \mathrm { R } _ { 4 } = 4 \mathrm { k } \Omega  Use superposition principle to find  V _ { 1 } .

Correct Answer:

verifed

Verified

If the current source is deactivated by ...

View Answer

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions