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Let f(x)=x312x+1f ( x ) = x ^ { 3 } - 12 x + 1

Question 60

Multiple Choice

Let f(x) =x312x+1f ( x ) = x ^ { 3 } - 12 x + 1 on [3,0][ - 3,0 ] The absolute minimum and maximum of ƒ are located respectively at x =


A) -3,0
B) -2,0
C) 0,-3
D) 0,-2
E) -3,-2

Correct Answer:

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