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The General Solution of the First-Order Differential Equation (x+1)y2y=(x+1)4( x + 1 ) y ^ { \prime } - 2 y = ( x + 1 ) ^ { 4 }

Question 23

Multiple Choice

The general solution of the first-order differential equation (x+1) y2y=(x+1) 4( x + 1 ) y ^ { \prime } - 2 y = ( x + 1 ) ^ { 4 } is


A) 2y=(x+1) 4+C(x+1) 22 y = ( x + 1 ) ^ { 4 } + C ( x + 1 ) ^ { 2 }
B) 2y=(x+1) 4C(x+1) 22 y = ( x + 1 ) ^ { 4 } - C ( x + 1 ) ^ { 2 }
C) 3y=(x+1) 4+C(x+1) 23 y = ( x + 1 ) ^ { 4 } + C ( x + 1 ) ^ { 2 }
D) 3y=(x+1) 4C(x+1) 23 y = ( x + 1 ) ^ { 4 } - C ( x + 1 ) ^ { 2 }
E) 4y=(x+1) 4+C(x+1) 24 y = ( x + 1 ) ^ { 4 } + C ( x + 1 ) ^ { 2 }

Correct Answer:

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