Solved

If I = \int C (yx1)dx+(ln(2x2)+1y)dy\left( \frac { y } { x - 1 } \right) d x + \left( \ln ( 2 x - 2 ) + \frac { 1 } { y } \right) d y

Question 166

Multiple Choice

If I = \int C (yx1) dx+(ln(2x2) +1y) dy\left( \frac { y } { x - 1 } \right) d x + \left( \ln ( 2 x - 2 ) + \frac { 1 } { y } \right) d y is independent of the path where C is a curve from (3, 1) to (2, 2) , then I is


A) 0
B) ln2\ln 2
C) ln3\ln 3
D) ln5\ln 5
E) ln6\ln 6

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