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Let F(x,y,z)=x2i+y2j+z2k\mathbf { F } ( x , y , z ) = x ^ { 2 } \mathbf { i } + y ^ { 2 } \mathbf { j } + z ^ { 2 } \mathbf { k }

Question 142

Multiple Choice

Let F(x,y,z) =x2i+y2j+z2k\mathbf { F } ( x , y , z ) = x ^ { 2 } \mathbf { i } + y ^ { 2 } \mathbf { j } + z ^ { 2 } \mathbf { k } and S is x2+y2+z2=4x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 4 . Using the Divergence Theorem, S\iint S FndS\mathbf { F } \bullet \mathbf { n } d S is


A) 4
B) 2
C) 0
D) 2- 2
E) 4- 4

Correct Answer:

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