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Let $I = \int _ { 0 } ^ { 2 } \left[ \int _ { 0 } ^ { \sqrt { 4 - x ^ { 2 } } } d y \right] d x$

Question 169

Multiple Choice

Let $I = \int _ { 0 } ^ { 2 } \left[ \int _ { 0 } ^ { \sqrt { 4 - x ^ { 2 } } } d y \right] d x$ Then I in polar form is

A) $\int _ { \frac { \pi } { 2 } } ^ { \pi } \left[ \int _ { 0 } ^ { 2 } r d r \right] d \theta$
B) $\int _ { 0 } ^ { \pi } \left[ \int _ { 0 } ^ { 2 } d r \right] d \theta$
C) $\int _ { 0 } ^ { \pi } \left[ \int _ { 0 } ^ { 2 } r d r \right] d \theta$
D) $\int _ { 0 } ^ { \frac { \pi } { 2 } } \left[ \int _ { 0 } ^ { 2 } d r \right] d \theta$
E) $\int _ { 0 } ^ { \frac { \pi } { 2 } } \left[ \int _ { 0 } ^ { 2 } r d r \right] d \theta$

Let I=∫02[∫04−x2dy]dxI = \int _ { 0 } ^ { 2 } \left[ \int _ { 0 } ^ { \sqrt { 4 - x ^ { 2 } } } d y \right] d xI=∫02​[∫04−x2​​dy]dx

Multiple Choice

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Let $I = \int _ { 0 } ^ { 2 } \left[ \int _ { 0 } ^ { \sqrt { 4 - x ^ { 2 } } } d y \right] d x$

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