Solved

The Center of Mass of a Lamina in the Shape r=2(1+sinθ)r = 2 ( 1 + \sin \theta )

Question 39

Multiple Choice

The center of mass of a lamina in the shape of a region in the xy-plane bounded by r=2(1+sinθ) r = 2 ( 1 + \sin \theta ) with area density ρ(r,θ) =r\rho ( r , \theta ) = r is


A) (1528,58) \left( \frac { 15 } { 28 } , \frac { 5 } { 8 } \right)
B) (0,2110) \left( 0 , \frac { 21 } { 10 } \right)
C) (45,45) \left( \frac { 4 } { 5 } , \frac { 4 } { 5 } \right)
D) (125,185) \left( \frac { 12 } { 5 } , \frac { 18 } { 5 } \right)
E) (85,85) \left( \frac { 8 } { 5 } , \frac { 8 } { 5 } \right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions