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The Surface Area of the Surface in the First Octant x2+y2=z2x ^ { 2 } + y ^ { 2 } = z ^ { 2 }

Question 37

Multiple Choice

The surface area of the surface in the first octant cut from x2+y2=z2x ^ { 2 } + y ^ { 2 } = z ^ { 2 } by x + y = 4 is


A) 636 \sqrt { 3 }
B) 464 \sqrt { 6 }
C) 626 \sqrt { 2 }
D) 828 \sqrt { 2 }
E) 9

Correct Answer:

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