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At Moderate Temperatures, the Rate Law for the Reaction of NO2

Question 48

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At moderate temperatures, the rate law for the reaction of NO2 and CO to give CO2 and NO follows the rate law shown below:rate = k [NO2]2 At moderate temperatures, the rate law for the reaction of NO<sub>2</sub> and CO to give CO<sub>2</sub> and NO follows the rate law shown below:rate = k [NO<sub>2</sub>]<sup>2</sup> In which flask will the reaction be faster and how much faster? In which flask will the reaction be faster and how much faster?

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flask b; f...

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